VKR (diploma) – issuing a qualifying work by an institute (university) student. Examples of in-text bibliographic references

VKR (diploma) – issuing a qualifying work by an institute (university) student.  Examples of in-text bibliographic references
VKR (diploma) – issuing a qualifying work by an institute (university) student. Examples of in-text bibliographic references

1. Moment impulse, Mdt, acting on rotational body, is equal to the change in its angular momentum dL:
Mdt = d(J ω) or Mdt = dL
Where: Mdt – impulse of the moment of force (the product of the moment of force M by the time interval dt)
Jdω = d(Jω) – change in the angular momentum of the body,
Jω = L - the angular momentum of a body is the product of the moment of inertia J and the angular velocity ω ω, and d(Jω) is dL.

2. Kinematic characteristics Rotation of a rigid body as a whole is characterized by an angle φ, measured in angular degrees or radians, angular velocity
ω = dφ/dt
(measured in rad/s)
and angular acceleration
ε = d²φ/dt² (measured in rad/s²).
With uniform rotation (T revolutions per second), Rotation frequency is the number of body revolutions per unit time:
f = 1/T =
ω/2
The rotation period is the time of one full revolution. The rotation period T and its frequency f are related by the relation
T = 1/f

Linear speed of a point located at a distance R from the axis of rotation

Angular velocity of body rotation
ω = f/Dt = 2/T

Dynamic characteristics The properties of a rigid body during its rotation are described by the moment of inertia solid. This feature is included in differential equations, obtained from Hamilton's or Lagrange's equations. The kinetic energy of rotation can be written as:
E=

In this formula, the moment of inertia plays the role of mass, and angular velocity plays the role normal speed. The moment of inertia expresses the geometric distribution of mass in a body and can be found from the formula:

The moment of inertia of a mechanical system relative to a fixed axis a (“axial moment of inertia”) is a physical quantity Ja equal to the sum of the products of the masses of all n material points systems by the squares of their distances to the axis:
= ∑

Where: mi is the mass of the i-th point, ri is the distance from the i-th point to the axis. The axial moment of inertia of a body Ja is a measure of the inertia of a body in rotational motion around axis a, just as the mass of a body is a measure of its inertia in translational motion.

3. The pendulum represents closed system.
If the pendulum is in extreme point, its potential energy is maximum, and its kinetic energy is zero.
As soon as the pendulum begins to move, its potential energy decreases, and its kinetic energy increases.
At the bottom point, kinetic energy is maximum and potential energy is minimum. After this, the reverse process begins. The accumulated kinetic energy moves the pendulum upward and thereby increases the potential energy of the pendulum. Kinetic energy decreases until the pendulum stops again at the other extreme point.
We can say that during the movement of the pendulum a transition occurs potential energy to kinetic and vice versa.

The sum of the kinetic and potential energy of the bodies that make up a closed system and interact with each other by gravitational and elastic forces remains constant.
Or this: The total mechanical energy of a closed system of bodies interacting with gravitational and elastic forces remains unchanged.
(The sum of the kinetic and potential energy of bodies is called total mechanical energy)

To derive this law, let us consider the simplest case of rotational motion of a material point. Let us decompose the force acting on a material point into two components: normal - and tangent - (Fig. 4.3). The normal component of the force will lead to the appearance of normal (centripetal) acceleration: ; , where r = OA - radius of the circle.

A tangential force will cause a tangential acceleration to appear. In accordance with Newton's second law, F t =ma t or F cos a=ma t.

Let's express the tangential acceleration in terms of the angular acceleration: a t =re. Then F cos a=mre. Let's multiply this expression by the radius r: Fr cos a=mr 2 e. Let us introduce the notation r cos a = l , Where l - leverage of force, i.e. length of the perpendicular lowered from the axis of rotation to the line of action of the force. Sincemr 2 =I - moment of inertia of a material point, and product = Fl = M - moment of force, then

Product of moment of force M for the duration of its validity dt is called the moment impulse. Product of moment of inertia I by angular velocity w is called the angular momentum of the body: L=Iw. Then the basic law of the dynamics of rotational motion in the form (4.5) can be formulated as follows: The momentum of the moment of force is equal to the change in the angular momentum of the body. In this formulation, this law is similar to Newton’s second law in the form (2.2).

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Let us consider a closed conservative system of bodies. This means that the bodies of the system are not acted upon by external forces, but internal forces are conservative by nature. Full mechanical

Collisions
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Let us consider an isolated body, i.e. a body that is not acted upon by an external moment of force. Then Mdt = 0 and from (4.5) it follows d(Iw)=0, i.e. Iw=const. If an isolated system consists

Gyroscope
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Derivation of the basic law of the dynamics of rotational motion. To the derivation of the basic equation of the dynamics of rotational motion. Dynamics of rotational motion of a material point. In projection onto the tangential direction, the equation of motion will take the form: Ft = mt.

15. Derivation of the basic law of the dynamics of rotational motion.

Rice. 8.5. To the derivation of the basic equation of the dynamics of rotational motion.

Dynamics of rotational motion of a material point.Consider a particle of mass m rotating around a current O along a circle of radius R , under the action of the resultant force F (see Fig. 8.5). IN inertial system counting is fair 2 Ouch Newton's law. Let's write it in relation to an arbitrary moment in time:

F = m·a.

The normal component of the force is not capable of causing rotation of the body, so we will consider only the action of its tangential component. In projection onto the tangential direction, the equation of motion will take the form:

F t = m·a t .

Since a t = e·R, then

F t = m e R (8.6)

Multiplying the left and right sides of the equation scalarly by R, we get:

F t R= m e R 2 (8.7)
M = Ie. (8.8)

Equation (8.8) represents 2 Ouch Newton's law (equation of dynamics) for the rotational motion of a material point. It can be given a vector character, taking into account that the presence of a torque causes the appearance of a parallel angular acceleration vector directed along the axis of rotation (see Fig. 8.5):

M = I·e. (8.9)

The basic law of the dynamics of a material point during rotational motion can be formulated as follows:

the product of the moment of inertia and angular acceleration is equal to the resulting moment of forces acting on a material point.


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Dynamics of rotational motion

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Dynamics of rotational motion

Preface

I draw students' attention to the fact that THIS material was not considered ABSOLUTELY at school (except for the concept of moment of force).

1. Law of dynamics of rotational motion

a. Law of dynamics of rotational motion

b. Moment of power

c. Moment of a couple of forces

d. Moment of inertia

2. Moments of inertia of some bodies:

a. Ring (thin-walled cylinder)

b. Thick wall cylinder

c. Solid cylinder

e. Thin rod

3. Steiner's theorem

4. Momentum of the body. Change in angular momentum of a body. Momentum impulse. Law of conservation of angular momentum

5. Rotary work

6. Kinetic energy of rotation

7. Comparison of quantities and laws for translational and rotational motion

1a. Let's consider a rigid body that can rotate around a fixed axis OO (Fig. 3.1). Let's break this solid body into separate elementary masses Δ m i. The resultant of all forces applied to Δ m i, denote by . It is enough to consider the case when the force lies in a plane perpendicular to the axis of rotation: components of forces parallel to the axis cannot influence the rotation of the body, since the axis is fixed. Then the equation of Newton’s second law for the tangential components of force and acceleration will be written as:

. (3.1)

The normal component of the force provides centripetal acceleration and does not affect angular acceleration. From (1.27): ,where is the radius of rotation i-that point. Then

. (3.2)

Let's multiply both sides (3.2) by:

notice, that

where α is the angle between the force vector and the radius vector of the point (Fig. 3.1), is the perpendicular lowered to the line of action of the force from the center of rotation (force arm). Let's introduce the concept of moment of force.

1b. A moment of power relative to the axis is a vector directed along the axis of rotation and related to the direction of the force by the gimlet rule, the module of which is equal to the product of the force by its arm: . Shoulder of power l relative to the axis of rotation - this is the shortest distance from the line of action of the force to the axis of rotation. Dimension of moment of force:

In vector form, the moment of force about a point:

The vector of the moment of force is perpendicular to both the force and the radius vector of the point of its application:

If the force vector is perpendicular to the axis, then the force moment vector is directed along the axis according to the right screw rule, and the magnitude of the force moment relative to this axis (projection onto the axis) is determined by formula (3.4):

The moment of force depends on both the magnitude of the force and the leverage of the force. If the force is parallel to the axis, then .

1c. Couple of forces - these are two forces equal in magnitude and opposite in direction, the lines of action of which do not coincide (Fig. 3.2). The arm of a force pair is the distance between the lines of action of the forces. Let's find the total moment of the pair of forces u () in projection onto the axis passing through point O:

That is, the moment of a pair of forces is equal to the product of the magnitude of the force by the plccho of the pair:

. (3.6)

Let's return to (3.3). Taking into account (3.4) and (3.6):

. (3.7)

1d. Definition: a scalar quantity equal to the product of the mass of a material point by the square of its distance to the axis is called moment of inertia of a material point relative to the axis OO:

Dimension of moment of inertia

The vectors and coincide in direction with the axis of rotation and are related to the direction of rotation according to the gimlet rule, therefore equality (3.9) can be rewritten in vector form:

. (3.10)

Let us sum (3.10) over all elementary masses into which the body is divided:

. (3.11)

Here it is taken into account that the angular acceleration of all points of a rigid body is the same, and it can be taken out of the sum sign. On the left side of the equality is the sum of the moments of all forces (both external and internal) applied to each point of the body. But according to Newton's third law, the forces with which the points of the body interact with each other (internal forces) are equal in magnitude and opposite in direction and lie on the same straight line, so their moments cancel each other out. Thus, on the left side of (3.11) the total moment remains only external forces: .

The sum of the products of elementary masses by the square of their distances from the axis of rotation is called moment of inertia of a rigid body relative to this axis:

. (3.12)

Thus, ; - this is the basic law of the dynamics of rotational motion of a rigid body (analogue of Newton’s second law): the angular acceleration of a body is directly proportional to the total moment of external forces and inversely proportional to the moment of inertia of the body :

. (3.13)

Moment of inertia Isolid body is a measure of the inert properties of a solid body during rotational motion and is similar to the mass of a body in Newton's second law. It significantly depends not only on the body mass, but also on its distribution relative to the axis of rotation (in the direction perpendicular to the axis).

In the case of continuous mass distribution, the sum in (3.12) is reduced to the integral over the entire volume of the body:

2a. The moment of inertia of a thin ring about an axis passing through its center perpendicular to the plane of the ring.

,

since for any element of the ring its distance to the axis is the same and equal to the radius of the ring: .

2b. Thick-walled cylinder (disc) with an inner radius and an outer radius.

Let us calculate the moment of inertia of a homogeneous disk with density ρ , height h, internal radius and external radius (Fig. 3.3) relative to the axis passing through the center of mass perpendicular to the plane of the disk. Let us divide the disk into thin rings of thickness and height so that the inner radius of the ring is equal to , and the outer radius is equal to . The volume of such a ring, where – area of ​​the base of the thin ring. Its mass:

Let us substitute into (3.14) and integrate over r():



Disk mass, then finally:

. (3.17)

2c. Solid cylinder (disc).

In the particular case of a solid disk or cylinder with a radius R let's substitute into (3.17) R 1 =0, R 2 =R and we get:

. (3.18)

Moment of inertia of a ball of radius R and the mass relative to the axis passing through its center (Fig. 3.4) is equal to (without proof):


2e. The moment of inertia of a thin rod of mass and length relative to an axis passing through its end perpendicular to the rod (Fig. 3.5).

Let us divide the rod into infinitesimal sections of length . The mass of such a section. Let's substitute in (3.14) and integrate from 0 to :

If the axis passes through the center of the rod perpendicular to it, you can calculate the moment of inertia of half the rod using (3.20) and then double it:

. (3.21)

3. If the axis of rotation doesn't work through the center of mass of the body (Fig. 3.6), calculations using formula (3.14) can be quite complex. In this case, the calculation of the moment of inertia is simplified by using Steiner's theorem : the moment of inertia of the body relative to an arbitrary axis is equal to the sum of the moment of inertia I c body relative to an axis passing through the center of mass of the body parallel to this axis, and the product of the body mass by the square of the distance between axes:

. (3.22)

Let's see how Steiner's theorem works if we apply it to a rod:

It is easy to verify that an identity is obtained, since in this case the distance between the axes is equal to half the length of the rod.

4. Momentum of the body. Change in angular momentum of a body. Momentum impulse. Law of conservation of angular momentum.

From the law of dynamics of rotational motion and the definition of angular acceleration it follows:

.

If, then. Let us introduce the angular momentum of a rigid body as

Relationship (3.24) is the basic law of rigid body dynamics for rotational motion. It can be rewritten like this:

and then this will be an analogue of Newton's second law for forward movement in pulse form (2.5)

Expression (3.24) can be integrated:

and formulate the law of change in angular momentum: the change in angular momentum of the body is equal to the impulse of the total moment of external forces . The quantity is called the impulse of the moment of force and is similar to the impulse of force in the formulation of Newton's second law for translational motion (2.2); angular momentum is analogous to momentum.

Dimension of angular momentum

The angular momentum of a rigid body relative to its axis of rotation is a vector directed along the axis of rotation according to the gimlet rule.

The angular momentum of a material point relative to point O (Fig. 3.6) is:

where is the radius vector of the material point, is its momentum. The angular momentum vector is directed according to the gimlet rule perpendicular to the plane in which the vectors and lie: in Fig. 3.7 - towards us due to the figure. Magnitude of angular momentum

Let us divide a rigid body rotating about an axis into elementary masses and sum up the angular momentum of each mass over the entire body (the same can be written in the form of an integral; this is not important):

.

Since the angular velocity of all points is the same and is directed along the axis of rotation, we can write it in vector form:

Thus, the equivalence of definitions (3.23) and (3.26) is proven.

If the total moment of external forces is zero, then the angular momentum of the system does not change(see 3.25):

. This is the law of conservation of angular momentum . This is possible when:

a) the system is closed (or );

b) external forces have no tangential components (the force vector passes through the axis/center of rotation);

c) external forces are parallel to the fixed axis of rotation.

Examples of the use/action of the law of conservation of angular momentum:

1. gyroscope;

2. Zhukovsky bench;

3. figure skater on ice.

5. Work in rotational motion.

Let the body rotate through an angle under the action of a force and the angle between the displacement and the force is equal to ; – radius vector of the point of application of the force (Fig. 3.8), then the work of the force is equal.

In an inertial reference frame, the angular acceleration acquired by a body rotating about a fixed axis is proportional to the total moment of all external forces acting on the body, and inversely proportional to the moment of inertia of the body relative to a given axis:

A simpler formulation can be given main law of rotational dynamics (it is also called Newton's second law for rotational motion) : torque is equal to the product of the moment of inertia and angular acceleration:

moment of impulse(angular momentum, angular momentum) of a body is called the product of its moment of inertia and angular velocity:

Momentum– vector quantity. Its direction coincides with the direction of the angular velocity vector.

The change in angular momentum is determined as follows:

. (I.112)

A change in angular momentum (with a constant moment of inertia of the body) can occur only as a result of a change in angular velocity and is always due to the action of a moment of force.

According to the formula, as well as formulas (I.110) and (I.112), the change in angular momentum can be represented as:

. (I.113)

The product in formula (I.113) is called momentum impulse or driving force. It is equal to the change in angular momentum.

Formula (I.113) is valid provided that the moment of force does not change over time. If the moment of force depends on time, i.e. , That

. (I.114)

Formula (I.114) shows that: the change in angular momentum is equal to the time integral of the moment of force. In addition, if this formula is presented in the form: , then the definition will follow from it moment of force: instantaneous torque is the first derivative of angular momentum with respect to time,

Expression (I.115) is another form basic equation (law ) dynamics of rotational motion of a rigid body relative to the fixed axis: the derivative of the angular momentum of a rigid body relative to an axis is equal to the moment of force relative to the same axis.

Question 15

Moment of inertia



The moment of inertia of a system (body) relative to a given axis is a physical quantity equal to the sum of the products of masses n material points of the system by the squares of their distance to the axis under consideration:

J=

The summation is performed over all elementary masses m(i) into which the body is divided

In the case of a continuous mass distribution, this sum reduces to the integral

where integration is carried out over the entire volume of the body. The value of z in this case is a function of the position of the point with coordinates x, y, z.

As an example, let us find the moment of inertia of a homogeneous solid cylinder of height h and radius R relative to its geometric axis. Let us divide the cylinder into separate hollow concentric cylinders of infinitesimal thickness dr with an internal radius r and an external radius r + dr. The moment of inertia of each hollow cylinder d,/ = r^2 dm (since dr≤r we assume that the distance of all points of the cylinder from the axis is equal to r), where dm is the mass of the entire elementary cylinder; its volume is 2 πr hrd r. If p is the density of the material, then dm = 2πhpr^3d r. Then the moment of inertia of a solid cylinder

but since πR^3h is the volume of the cylinder, then its mass m= πR^2hp, and the moment of inertia

Steiner's theorem

The moment of inertia of a body J relative to an arbitrary axis is equal to its moment of inertia relative to a parallel axis passing through the center of mass C of the body, added to the product of the body mass and the square of the distance a between the axes:

J= +ma^2

1. Moment of inertia of a homogeneous straight thin cylindrical rod length and mass relative to an axis passing through its middle and perpendicular to its length:

2. Moment of inertia of a homogeneous solid cylinder(or disk) radius and mass relative to the axis of symmetry perpendicular to its plane and passing through its center:

3. Moment of inertia of the cylinder radius, mass and height relative to an axis perpendicular to its height and passing through its middle:

4. Moment of inertia of the ball(thin-walled sphere) radius and mass relative to its diameter (or axis passing through the center of the sphere):

5. Moment of inertia of the rod length and mass relative to an axis passing through one of its ends and perpendicular to its length:

6. Moment of inertia of a hollow thin-walled cylinder radius and mass, relative to the cylinder axis:

7. Moment of inertia of a cylinder with a hole(wheel, clutch):

,

where and are the radii of the cylinder and the hole in it. The angular momentum is also constant for open systems if the resulting moment of external forces applied to the system is zero.

A gyroscope (example: spinning top) is a symmetrical body rotating around its axis at high speed.

The angular momentum of the gyroscope coincides with its axis of rotation.

Electric charge is a measure of the participation of bodies in electromagnetic interactions.

There are two kinds electric charges, conventionally called positive and negative.

Coulomb's Law:

.

Electric field is a special form of matter through which interaction between charged particles occurs.

Tension electric field– vector physical quantity. The direction of the tension vector coincides at each point in space with the direction of the force acting on the positive test charge.

Power lines Coulomb fields of positive and negative point charges: