The triangle is a figure familiar to everyone. And this despite the rich variety of its forms. Rectangular, equilateral, acute, isosceles, obtuse. Each of them is different in some way. But for anyone you need to find out the area of ​​a triangle.

Formulas common to all triangles that use the lengths of sides or heights

The designations adopted in them: sides - a, b, c; heights on the corresponding sides on a, n in, n with.

1. The area of ​​a triangle is calculated as the product of ½, a side and the height subtracted from it. S = ½ * a * n a. The formulas for the other two sides should be written similarly.

2. Heron's formula, in which the semi-perimeter appears (it is usually denoted by the small letter p, in contrast to the full perimeter). The semi-perimeter must be calculated as follows: add up all the sides and divide them by 2. The formula for the semi-perimeter is: p = (a+b+c) / 2. Then the equality for the area of ​​the figure looks like this: S = √ (p * (p - a) * ( р - в) * (р - с)).

3. If you don’t want to use a semi-perimeter, then a formula that contains only the lengths of the sides will be useful: S = ¼ * √ ((a + b + c) * (b + c - a) * (a + c - c) * (a + b - c)). It is slightly longer than the previous one, but it will help out if you have forgotten how to find the semi-perimeter.

General formulas involving the angles of a triangle

Notations required to read the formulas: α, β, γ - angles. They lie opposite sides a, b, c, respectively.

1. According to it, half the product of two sides and the sine of the angle between them is equal to the area of ​​the triangle. That is: S = ½ a * b * sin γ. The formulas for the other two cases should be written in a similar way.

2. The area of ​​a triangle can be calculated from one side and three known angles. S = (a 2 * sin β * sin γ) / (2 sin α).

3. There is also a formula with one known party and two adjacent angles. It looks like this: S = c 2 / (2 (ctg α + ctg β)).

The last two formulas are not the simplest. It's quite difficult to remember them.

General formulas for the situation when the radii of inscribed or circumscribed circles are known

Additional designations: r, R - radii. The first is used for the radius of the inscribed circle. The second is for the one described.

1. The first formula by which the area of ​​a triangle is calculated is related to the semi-perimeter. S = r * r. Another way to write it is: S = ½ r * (a + b + c).

2. In the second case, you will need to multiply all the sides of the triangle and divide them by quadruple the radius of the circumscribed circle. In literal expression it looks like this: S = (a * b * c) / (4R).

3. The third situation allows you to do without knowing the sides, but you will need the values ​​of all three angles. S = 2 R 2 * sin α * sin β * sin γ.

Special case: right triangle

This is the most simple situation, since only the length of both legs is required. They are designated by the Latin letters a and b. Square right triangle equal to half the area of ​​the rectangle added to it.

Mathematically it looks like this: S = ½ a * b. It is the easiest to remember. Because it looks like the formula for the area of ​​a rectangle, only a fraction appears, indicating half.

Special case: isosceles triangle

Since it has two equal sides, some formulas for its area look somewhat simplified. For example, Heron's formula, which calculates the area isosceles triangle, takes the following form:

S = ½ in √((a + ½ in)*(a - ½ in)).

If you transform it, it will become shorter. In this case, Heron’s formula for an isosceles triangle is written as follows:

S = ¼ in √(4 * a 2 - b 2).

The area formula looks somewhat simpler than for an arbitrary triangle if the sides and the angle between them are known. S = ½ a 2 * sin β.

Special case: equilateral triangle

Usually in problems the side about it is known or it can be found out in some way. Then the formula for finding the area of ​​such a triangle is as follows:

S = (a 2 √3) / 4.

Problems to find the area if the triangle is depicted on checkered paper

The simplest situation is when a right triangle is drawn so that its legs coincide with the lines of the paper. Then you just need to count the number of cells that fit into the legs. Then multiply them and divide by two.

When the triangle is acute or obtuse, it needs to be drawn to a rectangle. Then the resulting figure will have 3 triangles. One is the one given in the problem. And the other two are auxiliary and rectangular. The areas of the last two need to be determined using the method described above. Then calculate the area of ​​the rectangle and subtract from it those calculated for the auxiliary ones. The area of ​​the triangle is determined.

The situation in which none of the sides of the triangle coincides with the lines of the paper turns out to be much more complicated. Then it needs to be inscribed in a rectangle so that the vertices of the original figure lie on its sides. In this case, there will be three auxiliary right triangles.

Example of a problem using Heron's formula

Condition. Some triangle has known sides. They are equal to 3, 5 and 6 cm. You need to find out its area.

Now you can calculate the area of ​​the triangle using the above formula. Under the square root is the product of four numbers: 7, 4, 2 and 1. That is, the area is √(4 * 14) = 2 √(14).

If greater accuracy is not required, then you can take the square root of 14. It is equal to 3.74. Then the area will be 7.48.

Answer. S = 2 √14 cm 2 or 7.48 cm 2.

Example problem with right triangle

Condition. One leg of a right triangle is 31 cm larger than the second. You need to find out their lengths if the area of ​​the triangle is 180 cm 2.
Solution. We will have to solve a system of two equations. The first is related to area. The second is with the ratio of the legs, which is given in the problem.
180 = ½ a * b;

a = b + 31.
First, the value of “a” must be substituted into the first equation. It turns out: 180 = ½ (in + 31) * in. It has only one unknown quantity, so it is easy to solve. After opening the brackets we get quadratic equation: in 2 + 31 in - 360 = 0. It gives two values ​​for "in": 9 and - 40. The second number is not suitable as an answer, since the length of the side of a triangle cannot be a negative value.

It remains to calculate the second leg: add 31 to the resulting number. It turns out 40. These are the quantities sought in the problem.

Answer. The legs of the triangle are 9 and 40 cm.

Problem of finding a side through the area, side and angle of a triangle

Condition. The area of ​​a certain triangle is 60 cm 2. It is necessary to calculate one of its sides if the second side is 15 cm and the angle between them is 30º.

Solution. Based on the accepted notation, the desired side is “a”, the known side is “b”, the given angle is “γ”. Then the area formula can be rewritten as follows:

60 = ½ a * 15 * sin 30º. Here the sine of 30 degrees is 0.5.

After transformations, “a” turns out to be equal to 60 / (0.5 * 0.5 * 15). That is 16.

Answer. The required side is 16 cm.

Problem about a square inscribed in a right triangle

Condition. The vertex of a square with a side of 24 cm coincides with the right angle of the triangle. The other two lie on the sides. The third belongs to the hypotenuse. The length of one of the legs is 42 cm. What is the area of ​​the right triangle?

Solution. Consider two right triangles. The first one is the one specified in the task. The second one is based on the known leg of the original triangle. They are similar because they have a common angle and are formed by parallel lines.

Then the ratios of their legs are equal. The legs of the smaller triangle are equal to 24 cm (side of the square) and 18 cm (given leg 42 cm subtract the side of the square 24 cm). The corresponding legs of a large triangle are 42 cm and x cm. It is this “x” that is needed in order to calculate the area of ​​the triangle.

18/42 = 24/x, that is, x = 24 * 42 / 18 = 56 (cm).

Then the area is equal to the product of 56 and 42 divided by two, that is, 1176 cm 2.

Answer. The required area is 1176 cm 2.

From the opposite vertex) and divide the resulting product by two. This looks like this:

S = ½ * a * h,

Where:
S – area of ​​the triangle,
a is the length of its side,
h is the height lowered to this side.

Side length and height must be presented in the same units of measurement. In this case, the area of ​​the triangle will be obtained in the corresponding “ ” units.

Example.
On one side of a scalene triangle 20 cm long, a perpendicular from the opposite vertex 10 cm long is lowered.
The area of ​​the triangle is required.
Solution.
S = ½ * 20 * 10 = 100 (cm²).

If the lengths of any two sides of a scalene triangle and the angle between them are known, then use the formula:

S = ½ * a * b * sinγ,

where: a, b are the lengths of two arbitrary sides, and γ is the angle between them.

In practice, for example, when measuring land plots, the use of the above formulas is sometimes difficult, as it requires additional construction and measurement of angles.

If you know the lengths of all three sides of a scalene triangle, then use Heron's formula:

S = √(p(p-a)(p-b)(p-c)),

a, b, c – lengths of the sides of the triangle,
p – semi-perimeter: p = (a+b+c)/2.

If, in addition to the lengths of all sides, the radius of the circle inscribed in the triangle is known, then use the following compact formula:

where: r – radius of the inscribed circle (р – semi-perimeter).

To calculate the area of ​​a scalene triangle and the length of its sides, use the formula:

where: R – radius of the circumscribed circle.

If you know the length of one of the sides of the triangle and three angles (in principle, two are enough - the value of the third is calculated from the equality of the sum of the three angles of the triangle - 180º), then use the formula:

S = (a² * sinβ * sinγ)/2sinα,

where α is the value of the angle opposite to side a;
β, γ – values ​​of the remaining two angles of the triangle.

The need to find various elements, including areas triangle, appeared many centuries BC among learned astronomers Ancient Greece. Square triangle can be calculated different ways using different formulas. The calculation method depends on which elements triangle known.

Instructions

If from the condition we know the values ​​of two sides b, c and the angle formed by them?, then the area triangle ABC is found by the formula:
S = (bcsin?)/2.

If from the condition we know the values ​​of two sides a, b and the angle not formed by them?, then the area triangle ABC is found as follows:
Finding the angle?, sin? = bsin?/a, then use the table to determine the angle itself.
Finding the angle?, ? = 180°-?-?.
We find the area itself S = (absin?)/2.

If from the condition we know the values ​​of only three sides triangle a, b and c, then the area triangle ABC is found by the formula:
S = v(p(p-a)(p-b)(p-c)), where p is the semi-perimeter p = (a+b+c)/2

If from the problem conditions we know the height triangle h and the side to which this height is lowered, then the area triangle ABC according to the formula:
S = ah(a)/2 = bh(b)/2 = ch(c)/2.

If we know the meanings of the sides triangle a, b, c and the radius described about this triangle R, then the area of ​​this triangle ABC is determined by the formula:
S = abc/4R.
If three sides a, b, c and the radius of the inscribed in are known, then the area triangle ABC is found by the formula:
S = pr, where p is the semi-perimeter, p = (a+b+c)/2.

If ABC is equilateral, then the area is found by the formula:
S = (a^2v3)/4.
If triangle ABC is isosceles, then the area is determined by the formula:
S = (cv(4a^2-c^2))/4, where c – triangle.
If triangle ABC is right-angled, then the area is determined by the formula:
S = ab/2, where a and b are legs triangle.
If triangle ABC is a right isosceles triangle, then the area is determined by the formula:
S = c^2/4 = a^2/2, where c is the hypotenuse triangle, a=b – leg.

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• how to measure the area of ​​a triangle

Tip 3: How to find the area of ​​a triangle if the angle is known

Knowing just one parameter (the angle) is not enough to find the area tre square . If there are any additional sizes, then to determine the area you can choose one of the formulas in which the angle value is also used as one of the known variables. Several of the most frequently used formulas are given below.

Instructions

If, in addition to the size of the angle (γ) formed by the two sides tre square , the lengths of these sides (A and B) are also known, then square(S) of a figure can be defined as half the product of the lengths of the sides and the sine of this known angle: S=½×A×B×sin(γ).

Concept of area

The concept of the area of ​​any geometric figure, in particular a triangle, will be associated with a figure such as a square. For the unit area of ​​any geometric figure we will take the area of ​​a square whose side is equal to one. For completeness, let us recall two basic properties for the concept of areas of geometric figures.

Property 1: If geometric figures are equal, then their areas are also equal.

Property 2: Any figure can be divided into several figures. Moreover, the area of ​​the original figure is equal to the sum of the areas of all its constituent figures.

Let's look at an example.

Example 1

Obviously, one of the sides of the triangle is a diagonal of a rectangle, one side of which has a length of $5$ (since there are $5$ cells), and the other is $6$ (since there are $6$ cells). Therefore, the area of ​​this triangle will be equal to half of such a rectangle. The area of ​​the rectangle is

Then the area of ​​the triangle is equal to

Answer: $15$.

Next, we will consider several methods for finding the areas of triangles, namely using the height and base, using Heron’s formula and the area of ​​an equilateral triangle.

How to find the area of ​​a triangle using its height and base

Theorem 1

The area of ​​a triangle can be found as half the product of the length of a side and the height to that side.

Mathematically it looks like this

$S=\frac(1)(2)αh$

where $a$ is the length of the side, $h$ is the height drawn to it.

Proof.

Consider a triangle $ABC$ in which $AC=α$. The height $BH$ is drawn to this side, which is equal to $h$. Let's build it up to the square $AXYC$ as in Figure 2.

The area of ​​rectangle $AXBH$ is $h\cdot AH$, and the area of ​​rectangle $HBYC$ is $h\cdot HC$. Then

$S_ABH=\frac(1)(2)h\cdot AH$, $S_CBH=\frac(1)(2)h\cdot HC$

Therefore, the required area of ​​the triangle, by property 2, is equal to

$S=S_ABH+S_CBH=\frac(1)(2)h\cdot AH+\frac(1)(2)h\cdot HC=\frac(1)(2)h\cdot (AH+HC)=\ frac(1)(2)αh$

The theorem is proven.

Example 2

Find the area of ​​the triangle in the figure below if the cell has an area equal to one

The base of this triangle is equal to $9$ (since $9$ is $9$ squares). The height is also $9$. Then, by Theorem 1, we get

$S=\frac(1)(2)\cdot 9\cdot 9=40.5$

Answer: $40.5$.

Heron's formula

Theorem 2

If we are given three sides of a triangle $α$, $β$ and $γ$, then its area can be found as follows

$S=\sqrt(ρ(ρ-α)(ρ-β)(ρ-γ))$

here $ρ$ means the semi-perimeter of this triangle.

Proof.

Consider the following figure:

By the Pythagorean theorem, from the triangle $ABH$ we obtain

From the triangle $CBH$, according to the Pythagorean theorem, we have

$h^2=α^2-(β-x)^2$

$h^2=α^2-β^2+2βx-x^2$

From these two relations we obtain the equality

$γ^2-x^2=α^2-β^2+2βx-x^2$

$x=\frac(γ^2-α^2+β^2)(2β)$

$h^2=γ^2-(\frac(γ^2-α^2+β^2)(2β))^2$

$h^2=\frac((α^2-(γ-β)^2)((γ+β)^2-α^2))(4β^2)$

$h^2=\frac((α-γ+β)(α+γ-β)(γ+β-α)(γ+β+α))(4β^2)$

Since $ρ=\frac(α+β+γ)(2)$, then $α+β+γ=2ρ$, which means

$h^2=\frac(2ρ(2ρ-2γ)(2ρ-2β)(2ρ-2α))(4β^2)$

$h^2=\frac(4ρ(ρ-α)(ρ-β)(ρ-γ))(β^2 )$

$h=\sqrt(\frac(4ρ(ρ-α)(ρ-β)(ρ-γ))(β^2))$

$h=\frac(2)(β)\sqrt(ρ(ρ-α)(ρ-β)(ρ-γ))$

By Theorem 1, we get

$S=\frac(1)(2) βh=\frac(β)(2)\cdot \frac(2)(β) \sqrt(ρ(ρ-α)(ρ-β)(ρ-γ) )=\sqrt(ρ(ρ-α)(ρ-β)(ρ-γ))$

A triangle is like this geometric figure, which consists of three lines connecting at points that do not lie on the same line. The connection points of the lines are the vertices of the triangle, which are designated by Latin letters (for example, A, B, C). The connecting straight lines of a triangle are called segments, which are also usually denoted by Latin letters. Distinguish following types triangles:

• Rectangular.
• Obtuse.
• Acute angular.
• Versatile.
• Equilateral.
• Isosceles.

General formulas for calculating the area of ​​a triangle

Formula for the area of ​​a triangle based on length and height

S= a*h/2,
where a is the length of the side of the triangle whose area needs to be found, h is the length of the height drawn to the base.

Heron's formula

S=√р*(р-а)*(р-b)*(p-c),
where √ is Square root, p is the semi-perimeter of the triangle, a,b,c is the length of each side of the triangle. The semi-perimeter of a triangle can be calculated using the formula p=(a+b+c)/2.

Formula for the area of ​​a triangle based on the angle and the length of the segment

S = (a*b*sin(α))/2,
Where b,c is the length of the sides of the triangle, sin(α) is the sine of the angle between the two sides.

Formula for the area of ​​a triangle given the radius of the inscribed circle and three sides

S=p*r,
where p is the semi-perimeter of the triangle whose area needs to be found, r is the radius of the circle inscribed in this triangle.

Formula for the area of ​​a triangle based on three sides and the radius of the circle circumscribed around it

S= (a*b*c)/4*R,
where a,b,c is the length of each side of the triangle, R is the radius of the circle circumscribed around the triangle.

Formula for the area of ​​a triangle using the Cartesian coordinates of points

Cartesian coordinates of points are coordinates in the xOy system, where x is the abscissa, y is the ordinate. The Cartesian coordinate system xOy on a plane is the mutually perpendicular numerical axes Ox and Oy with a common origin at point O. If the coordinates of points on this plane are given in the form A(x1, y1), B(x2, y2) and C(x3, y3 ), then you can calculate the area of ​​the triangle using the following formula, which is obtained from vector product two vectors.
S = |(x1 – x3) (y2 – y3) – (x2 – x3) (y1 – y3)|/2,
where || stands for module.

How to find the area of ​​a right triangle

A right triangle is a triangle with one angle measuring 90 degrees. A triangle can have only one such angle.

Formula for the area of ​​a right triangle on two sides

S= a*b/2,
where a,b is the length of the legs. Legs are the sides adjacent to a right angle.

Formula for the area of ​​a right triangle based on the hypotenuse and acute angle

S = a*b*sin(α)/ 2,
where a, b are the legs of the triangle, and sin(α) is the sine of the angle at which the lines a, b intersect.

Formula for the area of ​​a right triangle based on the side and the opposite angle

S = a*b/2*tg(β),
where a, b are the legs of the triangle, tan(β) is the tangent of the angle at which the legs a, b are connected.

How to calculate the area of ​​an isosceles triangle

An isosceles triangle is one that has two equal sides. These sides are called the sides, and the other side is the base. To calculate the area of ​​an isosceles triangle, you can use one of the following formulas.

Basic formula for calculating the area of ​​an isosceles triangle

S=h*c/2,
where c is the base of the triangle, h is the height of the triangle lowered to the base.

Formula of an isosceles triangle based on side and base

S=(c/2)* √(a*a – c*c/4),
where c is the base of the triangle, a is the size of one of the sides of the isosceles triangle.

How to find the area of ​​an equilateral triangle

An equilateral triangle is a triangle in which all sides are equal. To calculate the area of ​​an equilateral triangle, you can use the following formula:
S = (√3*a*a)/4,
where a is the length of the side of the equilateral triangle.

The above formulas will allow you to calculate the required area of ​​the triangle. It is important to remember that to calculate the area of ​​triangles, you need to consider the type of triangle and the available data that can be used for the calculation.

To determine the area of ​​a triangle, you can use different formulas. Of all the methods, the easiest and most frequently used is to multiply the height by the length of the base and then divide the result by two. However this method far from the only one. Below you can read how to find the area of ​​a triangle using different formulas.

Separately, we will look at ways to calculate the area of ​​specific types of triangles - rectangular, isosceles and equilateral. We accompany each formula with a short explanation that will help you understand its essence.

Universal methods for finding the area of ​​a triangle

The formulas below use special notation. We will decipher each of them:

• a, b, c – the lengths of the three sides of the figure we are considering;
• r is the radius of the circle that can be inscribed in our triangle;
• R is the radius of the circle that can be described around it;
• α is the magnitude of the angle formed by sides b and c;
• β is the magnitude of the angle between a and c;
• γ is the magnitude of the angle formed by sides a and b;
• h is the height of our triangle, lowered from angle α to side a;
• p – half the sum of sides a, b and c.

It is logically clear why you can find the area of ​​a triangle in this way. The triangle can easily be completed into a parallelogram, in which one side of the triangle will act as a diagonal. The area of ​​a parallelogram is found by multiplying the length of one of its sides by the value of the height drawn to it. The diagonal divides this conditional parallelogram into 2 identical triangles. Therefore, it is quite obvious that the area of ​​our original triangle must be equal to half the area of ​​this auxiliary parallelogram.

S=½ a b sin γ

According to this formula, the area of ​​a triangle is found by multiplying the lengths of its two sides, that is, a and b, by the sine of the angle formed by them. This formula is logically derived from the previous one. If we lower the height from angle β to side b, then, according to the properties of a right triangle, when we multiply the length of side a by the sine of angle γ, we obtain the height of the triangle, that is, h.

The area of ​​the figure in question is found by multiplying half the radius of the circle that can be inscribed in it by its perimeter. In other words, we find the product of the semi-perimeter and the radius of the mentioned circle.

S= a b c/4R

According to this formula, the value we need can be found by dividing the product of the sides of the figure by 4 radii of the circle described around it.

These formulas are universal, as they make it possible to determine the area of ​​any triangle (scalene, isosceles, equilateral, rectangular). This can also be done using more complex calculations, which we will not dwell on in detail.

Areas of triangles with specific properties

How to find the area of ​​a right triangle? The peculiarity of this figure is that its two sides are simultaneously its heights. If a and b are legs, and c becomes the hypotenuse, then we find the area like this:

How to find the area of ​​an isosceles triangle? It has two sides with length a and one side with length b. Consequently, its area can be determined by dividing by 2 the product of the square of side a by the sine of angle γ.

How to find the area of ​​an equilateral triangle? In it, the length of all sides is equal to a, and the magnitude of all angles is α. Its height is equal to half the product of the length of side a and the square root of 3. To find the area of ​​a regular triangle, you need to multiply the square of side a by the square root of 3 and divide by 4.